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Answer on Question #43540 – Math – Vector Calculus
If a ⃗ = 2 i ⃗ − j ⃗ + k ⃗ \vec{a} = 2\vec{i} - \vec{j} + \vec{k} a = 2 i − j + k and b ⃗ = i ⃗ − 3 j ⃗ − 5 k ⃗ \vec{b} = \vec{i} - 3\vec{j} - 5\vec{k} b = i − 3 j − 5 k find a vector c ⃗ \vec{c} c such that a ⃗ , b ⃗ , c ⃗ \vec{a}, \vec{b}, \vec{c} a , b , c form the sides of a right angled triangle taken in order.
Solution.
Using the geometric interpretation of the vectors addition the hypotenuse c can be determined as a vector c ⃗ = − ( a ⃗ + b ⃗ ) \vec{c} = -\left(\vec{a} + \vec{b}\right) c = − ( a + b ) .
Write vectors a and b in three-dimensional Cartesian coordinates form
a ⃗ = ( 2 , − 1 , 1 ) b ⃗ = ( 1 , − 3 , − 5 ) \vec{a} = (2, -1, 1) \quad \vec{b} = (1, -3, -5) a = ( 2 , − 1 , 1 ) b = ( 1 , − 3 , − 5 )
Then
c ⃗ = − ( a ⃗ + b ⃗ ) = − ( 2 + 1 , − 1 − 3 , 1 − 5 ) \vec{c} = -\left(\vec{a} + \vec{b}\right) = -(2 + 1, -1 - 3, 1 - 5) c = − ( a + b ) = − ( 2 + 1 , − 1 − 3 , 1 − 5 ) c ⃗ = − ( 3 , − 4 , − 4 ) \vec{c} = -(3, -4, -4) c = − ( 3 , − 4 , − 4 ) c ⃗ = ( − 3 , 4 , 4 ) \vec{c} = (-3, 4, 4) c = ( − 3 , 4 , 4 )
Answer: c ⃗ = − 3 i ⃗ + 4 j ⃗ + 4 k ⃗ \vec{c} = -3\vec{i} + 4\vec{j} + 4\vec{k} c = − 3 i + 4 j + 4 k