Question #43540

If a ⃗=2i ⃗- j ⃗+ k ⃗ ,b ⃗= i ⃗- 3j ⃗-5k ⃗ find a vector c ⃗ such that a ⃗,b ⃗,c ⃗ form the sides of a right angled triangle taken in order .

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Answer on Question #43540 – Math – Vector Calculus

If a=2ij+k\vec{a} = 2\vec{i} - \vec{j} + \vec{k} and b=i3j5k\vec{b} = \vec{i} - 3\vec{j} - 5\vec{k} find a vector c\vec{c} such that a,b,c\vec{a}, \vec{b}, \vec{c} form the sides of a right angled triangle taken in order.

Solution.

Using the geometric interpretation of the vectors addition the hypotenuse c can be determined as a vector c=(a+b)\vec{c} = -\left(\vec{a} + \vec{b}\right).

Write vectors a and b in three-dimensional Cartesian coordinates form


a=(2,1,1)b=(1,3,5)\vec{a} = (2, -1, 1) \quad \vec{b} = (1, -3, -5)


Then


c=(a+b)=(2+1,13,15)\vec{c} = -\left(\vec{a} + \vec{b}\right) = -(2 + 1, -1 - 3, 1 - 5)c=(3,4,4)\vec{c} = -(3, -4, -4)c=(3,4,4)\vec{c} = (-3, 4, 4)


Answer: c=3i+4j+4k\vec{c} = -3\vec{i} + 4\vec{j} + 4\vec{k}

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