Question #32048

Given two vector A = 5i, B = 3j. Direction of (B x A) is ?

Expert's answer

Task. Given two vector A=5i\mathrm{A} = 5\mathrm{i}, B=3j\mathrm{B} = 3\mathrm{j}. What is the direction of the cross product [B×A][B \times A]?

Solution. Since [j×i]=k[j \times i] = -k, we obtain that [B×A]=15k[B \times A] = -15k.

We can produce direct calculation. We have that A=(5,0,0)=5iA = (5,0,0) = 5i, B=(0,3,0)=3jB = (0,3,0) = 3j. Then [B×A][B \times A] has the following coordinates:


[B×A]=(3000,0005,0350)=(3000,0500,0035)=(0,0,15)=15k.\begin{aligned} [B \times A] &= \left( \left| \begin{array}{cc} 3 & 0 \\ 0 & 0 \end{array} \right|, \left| \begin{array}{cc} 0 & 0 \\ 0 & 5 \end{array} \right|, \left| \begin{array}{cc} 0 & 3 \\ 5 & 0 \end{array} \right| \right) \\ &= (3 * 0 - 0 * 0, 0 * 5 - 0 * 0, 0 * 0 - 3 * 5) \\ &= (0, 0, -15) = -15k. \end{aligned}


Answer. [B×A]=15k[B \times A] = -15k.


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