Answer to Question #183596 in Vector Calculus for aman

Question #183596

An oil of sp.gr.0.8 is flowing through a Venturimeter having inlet diameter 20 cm and throat diameter 10 cm. The oil-mercury differential manometer shows a reading of 25 cm. Calculate the discharge of oil through the horizontal Venturimeter. Take Cd = 0.98.


1
Expert's answer
2021-05-11T13:55:40-0400

Given sp.gr of oil s0=0.8s_0 = 0.8

sp.gr of mercury sh=13.6s_h = 13.6

Reading of differential manometer = 25cm

We have that,

Difference of pressure head h=x[shs01]=25[13.60.81]=400cmh = x[\frac{s_h}{s_0}-1] = 25[\frac{13.6}{0.8}-1] = 400 cm of oil

Diameter of inlet (d1)=20cm(d_1) = 20cm

a1=πd124=400π4=314.16cm2a_1 = \frac{\pi d^2_1}{4} = \frac{400\pi}{4} = 314.16 cm^2

Diameter of throat (d2)=10cm(d_2) = 10cm

a2=πd224=100π4=78.54cm2a_2 = \frac{\pi d^2_2}{4} = \frac{100\pi}{4} = 78.54 cm^2

cd=0.98c_d = 0.98

The discharge Q of the oil is gotten using

Q=cda1a2a12a222ghQ =c_d \dfrac{a_1a_2}{\sqrt{a_1^2 - a_2^2}}\sqrt{2gh}

Q=0.98314.16×78.54314.16278.5422×9.8×400Q =0.98 \dfrac{314.16×78.54}{\sqrt{314.16^2 - 78.54^2}}\sqrt{2×9.8×400}

Q7,038cm3s1=7.038lts1Q \approx 7,038 cm^3s^{-1} = 7.038 lts^{-1}







Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment