Trigonometry Answers

If the wind speed is 60 mph and the velocity due to the thrust is 500 mph show that the resultant velocity R is
a. at an angle of 6.84 degrees to the thrust of the engines and
b. is about 504 mph
Show all working.

cosec2A-cot2A

sinAsin(60-A)sin(60+A)=1/4sin3A

what is the actual value of arc sin (-15/17) + arc sin (-30/36) . use arc sin x + arc sin y formula

what is the actual value of , arc tan [(-1)/(1)] , arc tan [(1)/(-1)] . do they have different value? then why ? both looks like arc tan [-1] which is -pi/4 . so now what is the actual value of arc sin [(-15)/(17)] , arc tan [(15)/(-17)] . do they have different value like arc tan or do they have same value ? then why ???

If arc sin x +arc sin y +arc sin z = pi . prove that [x *sqrt(1-x^2)] +[y *sqrt(1-y^2)]+[z *sqrt(1-z^2)] = 2xyz. show the process please

What is the actual value of arc sin(12/13) +arc sin(4/5)+arc sin(1). show the process using arc sinx +arc sin y formula?


using formula for the first two it comes pi - arc sin (56/65) then + arc sin 1 which is pi/2 . so the final result is 3pi/2 - arc sin (56/65) . and if i dont write pi/2 instead of arc sin 1 , then the result is pi - arc sin (56/65) +arc sin 1 = pi + arc sin (33/65) using formula for arc sin 1 - arc sin (56/65). i m lil bit confused which one is correct ? is there any use of principal value

the calculator shows its approximately 210 degree , means its a third quadrent angle .

normally we know arc sinx +arc sin y = arc sin [x*sqrt(1-y^2) +y*sqrt(1-x^2)]. but if we use this , the answer comes arc sin (56/65) + pi/2 , which does not match with the calculator result . so is there any regulation for arc sinx +arc sin y formula and is it applicable for (arc sinx +arc sin y) < pi/2 ?????

Without using tables or calculator,find the value of :
cos 900+1.

A 1
B 8
C 3
D2

Without using tables , find the value of sin600cos600

A 3√
B 3
C 1
D4√

Without using tables,find the value of 2sin300

A 5
B 4
C 3
D 2