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Trigonometry
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[tan^2x/(tan^2x-1)]+[cosec^2x/(sec^2x-cosec^2x)]=1/(sin^2x-cos^2x)
[tan^2x/(tan^2x-1)]+[cosec^2x/(sec^2x-cosec^2x)]=1/(sin^2x-cos^2x)
Trigonometry
Prove that
tan10tan50 + tan50tan70 + tan70tan170 = 3
tan10tan50 + tan50tan70 + tan70tan170 = 3
Trigonometry
sin(x+3y) + sin(3x+y) ÷ sin2x + sin2y = 2cos(x+y)
Trigonometry
If tan x = a and tan y = b
Show that sin(x+y) = (a+b) ÷ √(1+a^2)(1+b^2)
Show that sin(x+y) = (a+b) ÷ √(1+a^2)(1+b^2)
Trigonometry
If x=a*sinQ + b*cosQ and y=a*cosQ + b*sinQ
Prove that (x^2+y^2)(a^+y^2) - 4abxy = (a^2 - b^2)^2
Prove that (x^2+y^2)(a^+y^2) - 4abxy = (a^2 - b^2)^2
Trigonometry
cos55 degree ka solucation with proof giving the answer fast
Trigonometry
Two buildings are 25 m apart. From the top of the shorter
building, the angles of elevation and depression of the top and bottom
of the taller building are 31° and 48° respectively. What is the height
of the taller building? Give your answer to the nearest metre.
building, the angles of elevation and depression of the top and bottom
of the taller building are 31° and 48° respectively. What is the height
of the taller building? Give your answer to the nearest metre.
Trigonometry
Two surveyors A and B left P at the same time.A moved at a speed of 6km/hr on a bearing of 043degrees,while B moved at a speed of 4.5 km/hr on a bearing of 115degrees.calculate the distance between A and B after 4 hours and the Bearing of B from A
Trigonometry
(a) A box is resting on the ground and you can assume its location is the origin of the system. A person applies a force of 117 N to the box at angle of 305 degrees. Determine the horizontal component of the force applied to the box.
Trigonometry
A box is resting on the ground and you can assume its location is the origin of the system. A person applies a westward force of 31.7 Newtons (N) to the box while another applies a northward force of 43.5 N to the box. Determine the total force applied to the box.
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#340153 on Dec 2023
#340153 on Dec 2023