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WELL THE QUESTION IS (USING "A SQUARE +B SQUARE+C SQUARE" ,FIND THE LENGTH OF THE HYPOTENUSE OF THE TRIANGLE BELOW. SO, THE TRIANGLE HAS A=120 ,B=90 AND C=? SO WHAT THE ANSWER WOULD BE "C"?
please hepl me solve this question

(1+1/tan^2x)(1+1/cot^2x)=1/sin^2x-sin^4x
(1+1/tan^2x)(1+1/cot^2x)=1/sin^2x-sin^4x.please help me prove it.PLease
Prove: 1-(sec^6a+cos^6a)=3sin^2acos^2a
find the length of the arc subtended by a central angle of 352 degrees of a circle of radius 3 inches. give your answer to the nearest hundredth of an inch.
2cosA-sinA=x and cosA-sinA=y. Prove that 2x*x+y*y-2xy=5
Two vectors having equal magnitudes A make an angle θ with each other.The magnitude and direction of resultant are respectively:

a) 2Acos θ/2, along bisector
b) Acos θ/2, at 45 degree from one vector
c) Acos θ/2, along bisector

d)Asin θ/2, along bisector
If sin(x)=(1/11) (in quadrant 1)& find sin(2x)=
If cosecA=2,& & find the value of& 1/tanA + sinA/(1+cosA)
How do you find a second side of a triangle with using one side and two angles ?
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