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sin^2x+cos^2x
solve for x: 2cos^2x+3sinx=0
proof of 2cosxcosx+3sinx=0
the minimum value of 2^(sinx-1) + 2^(cosx-1) is
if acosx=b and x is acute; prove

sin(squared)x over 1-cosx = a+b over a
If sin A = cos A
find A
sin^2*2θ+6sin2θ+5=0 i have to solve for x
if 5 tan a = 4, show that , 5 sin a - 3 cos a/5 sin a + 2 cos a = 1/6
If sina + cos2a=1/2 and cosa +sin2a = 1/3
then find sin3a
cosθ/(cos(θ)+sin(θ)-1)-sin(θ)/(cos(θ)+sin(θ)-1)+1/(cos(θ)+sin(θ)-1)=csc(θ)+cot(θ)
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