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calculate the value of A if (sinA-1)(2cosA-1)=0
cos(pi/8)*cos(7pi/8)*cos(3pi/8)*cos(5pi/8)
1/sinA+cosA+1/sinA-cosA
Show that cos20°cos40°cos60°cos80°=1/16
sin20*sin40*sin60*sin80
cos20*cos40*cos60*cos80
sin[c]+sin[d]
If cos(alpha)+cos(beta)=0=sin(alpha)+sin(beta) then find the value of cos2(alpha)+cos2(beta)
Sin2x+Cos2x=1
[sin(4x) + sin(2x)] / [cos(4x) + cos(2x)] = √(3)
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