2012-05-25T07:23:05-04:00
solve on the interval [0, 2pi). tan(x)sec(x)=3tan(x)
1
2012-05-25T08:52:17-0400
tan ( x ) sec ( x ) = 3 tan ( x ) \tan (x) \sec (x) = 3 \tan (x) tan ( x ) sec ( x ) = 3 tan ( x ) tan ( x ) sec ( x ) = 3 tan ( x ) \tan (x) \sec (x) = 3 \tan (x) tan ( x ) sec ( x ) = 3 tan ( x ) sin x cos 2 x − 3 sin x cos x = 0 sin x = 0 x = 0 cos x = 1 3 x = arccos 1 3 = 1 , 230959 \begin{array}{l}
\frac{\sin x}{\cos^2 x} - 3 \frac{\sin x}{\cos x} = 0 \\
\sin x = 0 \quad x = 0 \\
\cos x = \frac{1}{3} \quad x = \arccos \frac{1}{3} = 1,230959 \\
\end{array} c o s 2 x s i n x − 3 c o s x s i n x = 0 sin x = 0 x = 0 cos x = 3 1 x = arccos 3 1 = 1 , 230959
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