Question #9994

solve on the interval [0, 2pi). tan(x)sec(x)=3tan(x)
1

Expert's answer

2012-05-25T08:52:17-0400
tan(x)sec(x)=3tan(x)\tan (x) \sec (x) = 3 \tan (x)tan(x)sec(x)=3tan(x)\tan (x) \sec (x) = 3 \tan (x)sinxcos2x3sinxcosx=0sinx=0x=0cosx=13x=arccos13=1,230959\begin{array}{l} \frac{\sin x}{\cos^2 x} - 3 \frac{\sin x}{\cos x} = 0 \\ \sin x = 0 \quad x = 0 \\ \cos x = \frac{1}{3} \quad x = \arccos \frac{1}{3} = 1,230959 \\ \end{array}

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