Answer to Question #90293 in Trigonometry for Michael

Question #90293
Cos3© is equivalent to
1
Expert's answer
2019-05-27T13:12:24-0400
"Cos(3x)=Cos(2x+x)=\\\\\n=Cos(2x)Cos(x)-Sin(2x)Sin(x)=\\\\\n=(Cos^2(x)-Sin^2(x))Cos(x)-2Sin(x)Cos(x)Sin(x)=\\\\\n=Cos^3(x)-3Sin^2(x)Cos(x)=\\\\\n=Cos^3(x)-3(1-Cos^2(x))Cos(x)=\\\\\n=4Cos^3(x)-3Cos(x)"


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