Solution
If A = 60°, B= 45° , C=30° then
tan A = tan 60°=sqrt(3)
cos B = cos 45°= sqrt(2)/2
sec C = sec 30°=2/sqrt(3)
Substitute: tan2A+4cos2B+3sec3C=(sqrt(3))2+4*(sqrt(2)/2)2+3*(2/sqrt(3))3=3+4*2/4+3*8/3sqrt(3)=3+2+8/sqrt(3)=9
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