Question #8556

Factor and simplify
Sin4x-cos4x

Expert's answer

sin4xcos4x=sin4xsin(π24x)=2sin(4xπ4)cos(π4)=2sin(4xπ4)22=2sin(4xπ4)\sin 4x - \cos 4x = \sin 4x - \sin \left(\frac {\pi}{2} - 4x\right) = 2 \sin \left(4x - \frac {\pi}{4}\right) \cos \left(\frac {\pi}{4}\right) = 2 \sin \left(4x - \frac {\pi}{4}\right) \frac {\sqrt {2}}{2} = \sqrt {2} \sin \left(4x - \frac {\pi}{4}\right)


Answer: sin4xcos4x=2sin(4xπ4)\sin 4x - \cos 4x = \sqrt{2} \sin \left(4x - \frac{\pi}{4}\right);

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