Question #83570

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Expert's answer

Answer on Question #83570 – Math – Trigonometry

Question

Jana is proving that the following trigonometric identity is true:


cos(θ)tanθ=sinθ\cos(-\theta) \tan \theta = \sin \theta


Which would be a correct first line of her proof?


cos(θ)tanθ=sinθ\cos(\theta) \tan \theta = \sin \thetacos(θ)tanθ=sin(θ)\cos(-\theta) \tan \theta = \sin(-\theta)cos(θ)tan(θ)=sin(θ)\cos(-\theta) \tan(-\theta) = \sin(-\theta)cos(θ)tan(θ)=sin(θ)\cos(\theta) \tan(-\theta) = \sin(\theta)


Solution

Due to the symmetry of cos(θ)\cos(\theta) (the cosine function is even, which means cos(θ)=cos(θ)\cos(-\theta) = \cos(\theta)), the equality


cos(θ)tan(θ)=sin(θ)\cos(-\theta) \tan(\theta) = \sin(\theta)


is transformed to


cos(θ)tan(θ)=sin(θ),\cos(\theta) \tan(\theta) = \sin(\theta),


which is also valid due to the definition of the tangent function


tan(θ)=sin(θ)cos(θ).\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}.


Answer: the correct first line would be cos(θ)tan(θ)=sin(θ)\cos(\theta) \tan(\theta) = \sin(\theta).

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