Question #77646

The earth is approximately 92.9 million miles from the sun, and 240,000 miles from the moon. When the angle sun-earth-moon is 25°, how far is the moon from the sun?

Expert's answer

Answer on Question #77646 – Math – Trigonometry

Question

The Earth is approximately 92.9 million miles from the Sun, and 240,000 miles from the Moon. When the angle Sun-Earth-Moon is 2525{}^{\circ}, how far is the Moon from the Sun?

Solution


Let’s set the Earth’s position as point EE, the Sun’s position as point SS and the Moon’s position as point MM. Then we have triangle SEMSEM as illustrated in the Figure, where


SE=9.29107 miles;|SE| = 9.29 \cdot 10^7 \text{ miles};ME=2.4105 miles;|ME| = 2.4 \cdot 10^5 \text{ miles};α=25.\alpha = 25{}^{\circ}.


According to the law of cosines:


MS2=SE2+ME22SEMEcosα,|MS|^2 = |SE|^2 + |ME|^2 - 2|SE||ME| \cos \alpha,MS2=(9.29107)2+(2.4105)229.291072.4105cos25.|MS|^2 = (9.29 \cdot 10^7)^2 + (2.4 \cdot 10^5)^2 - 2 \cdot 9.29 \cdot 10^7 \cdot 2.4 \cdot 10^5 \cdot \cos 25{}^{\circ}.


Concerning the fact that cos25=0.9063\cos 25{}^{\circ} = 0.9063, we have:


MS2=(9.29107)2+(2.4105)229.291072.41050.9063|MS|^2 = (9.29 \cdot 10^7)^2 + (2.4 \cdot 10^5)^2 - 2 \cdot 9.29 \cdot 10^7 \cdot 2.4 \cdot 10^5 \cdot 0.9063MS2=86.31014+5.76101044.591012|MS|^2 = 86.3 \cdot 10^{14} + 5.76 \cdot 10^{10} - 44.59 \cdot 10^{12}MS2=8630001010+5.76101044591010|MS|^2 = 863000 \cdot 10^{10} + 5.76 \cdot 10^{10} - 4459 \cdot 10^{10}MS2=858546.761010|MS|^2 = 858546.76 \cdot 10^{10}MS=926.6105=9.27107 miles.|MS| = 926.6 \cdot 10^5 = 9.27 \cdot 10^7 \text{ miles}.


So the Moon is 92.7 million miles from the Sun.

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