Answer to Question #74959 in Trigonometry for Anonymous
Given tanθ=3/4 and sin〖θ)]<0, find tan2θ.
a. 1/3 b. √5/3 c. 5/9 d. 24/7 e. None of these
1
2018-03-23T10:20:08-0400
If tan(θ)>0 and sin(θ)<0, then cos(θ)<0, and so:
tan(2θ) = (2tan(θ))/(1-〖tan〗^2 (θ)) = (2×(3/4))/(1-〖(3/4)〗^2 ) = 24/7
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