Question #69292

prove that (1+sinA)²+(1-sinA)²/cos²Α=2(1+sin²Α/1-sin²Α)

Expert's answer

Answer on Question #69292 – Math – Trigonometry

Question

Prove that


(1+sinA)2+(1sinA)2(cosA)2=21+(sinA)21(sinA)2\frac{(1 + \sin A)^2 + (1 - \sin A)^2}{(\cos A)^2} = 2 \frac{1 + (\sin A)^2}{1 - (\sin A)^2}


Solution


(1+sinA)2+(1sinA)2(cosA)2=1+2sinA+(sinA)2+12sinA+(sinA)2(cosA)2=2+2(sinA)2(cosA)2=21+(sinA)21(sinA)2.\frac{(1 + \sin A)^2 + (1 - \sin A)^2}{(\cos A)^2} = \frac{1 + 2 \sin A + (\sin A)^2 + 1 - 2 \sin A + (\sin A)^2}{(\cos A)^2} = \frac{2 + 2 (\sin A)^2}{(\cos A)^2} = 2 \frac{1 + (\sin A)^2}{1 - (\sin A)^2}.


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