Question #68512

sec alpha = 5/4, find value of tan alpha/1 + tan square alpha

Expert's answer

Answer on Question #68512 Math / Trigonometry

sec alpha = 5/4, find value of tan alpha/1 + tan square alpha

Solution:


secα=54\sec \alpha = \frac {5}{4}cosα=1secα=45,sinα=1cos2α=1(45)2=35.\cos \alpha = \frac {1}{\sec \alpha} = \frac {4}{5}, \sin \alpha = \sqrt {1 - \cos^ {2} \alpha} = \sqrt {1 - \left(\frac {4}{5}\right) ^ {2}} = \frac {3}{5}.tanα=sinαcosα=34\tan \alpha = \frac {\sin \alpha}{\cos \alpha} = \frac {3}{4}


So


tanα1+tan2α=341+(34)2=1225=0.48\frac {\tan \alpha}{1 + \tan^ {2} \alpha} = \frac {\frac {3}{4}}{1 + \left(\frac {3}{4}\right) ^ {2}} = \frac {12}{25} = 0.48


Answer: 1225=0.48\frac{12}{25} = 0.48

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