Answer on Question #63972 – Math – Trigonometry
Question
If tana=b/a, prove that acos2a+bsin2a=a.
Proof
It follows from tana=b/a that cosa=basina.
Substituting the previous formula into
acos2a+bsin2a=a(cos2a−sin2a)+b⋅2sinacosa==a(cos2a−sin2a)+b⋅2sina⋅basina=a(cos2a−sin2a)+2asin2a==a(cos2a+sin2a)=a
QED
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