Question #63972

if tana=b/a, prove that acos2a+bsin2a=a
1

Expert's answer

2016-12-16T10:08:10-0500

Answer on Question #63972 – Math – Trigonometry

Question

If tana=b/a\tan a = b / a, prove that acos2a+bsin2a=aa \cos 2a + b \sin 2a = a.

Proof

It follows from tana=b/a\tan a = b / a that cosa=absina\cos a = \frac{a}{b} \sin a.

Substituting the previous formula into


acos2a+bsin2a=a(cos2asin2a)+b2sinacosa==a(cos2asin2a)+b2sinaabsina=a(cos2asin2a)+2asin2a==a(cos2a+sin2a)=a\begin{array}{l} a \cos 2 a + b \sin 2 a = a \left(\cos^ {2} a - \sin^ {2} a\right) + b \cdot 2 \sin a \cos a = \\ = a \left(\cos^ {2} a - \sin^ {2} a\right) + b \cdot 2 \sin a \cdot \frac {a}{b} \sin a = a \left(\cos^ {2} a - \sin^ {2} a\right) + 2 a \sin^ {2} a = \\ = a \left(\cos^ {2} a + \sin^ {2} a\right) = a \end{array}


QED

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