Question

sin(x)=csc(x)

Answer 1

sin x=1/sin x
sin²x=1
So we have sin x=1 or sin x=-1

Consider the first equation sin x=1
hence x=pi/2+2k pi where k - integer

Consider the second equation sin x=-1
hence x=-pi/2+2k pi where k - integer

Therefore the answer is x=+-pi/2+2k pi where k - inetger