Answer to Question #61479 in Trigonometry for isa

Question

1 Integrate
∫(x3+3x2+2x+4)
∫(x3+3x2+2x+4)

x44+x3+x2+4x+c
x44+x3+x2+4x+c

x42−x3+x2+4x+c
x42−x3+x2+4x+c

3x44+2x3+x+c
3x44+2x3+x+c

6x4−3x2+c
6x4−3x2+c
2 Evaluate
∫(3x−2)6dx
∫(3x−2)6dx

(3x+2)72+c
(3x+2)72+c

(3x+2)721+c
(3x+2)721+c

(3x−2)721+c
(3x−2)721+c

3(3x−2)72+c
3(3x−2)72+c

Answer 1

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