Answer to Question #61478 in Trigonometry for isa

Question

9 Evaluate
∫x2e3xdx
∫x2e3xdx

e3x3(x2−2x3+29)+c
e3x3(x2−2x3+29)+c

−e3x3(x2+2x3−29)+c
−e3x3(x2+2x3−29)+c

e2x3(x3−x4+29)+c
e2x3(x3−x4+29)+c

ex3(x2+2x3−25)+c
ex3(x2+2x3−25)+c
10 Given f(x) =
(7x4−5x3)
(7x4−5x3)
, evaluate
df(x)dx
df(x)dx

7x4−5x3
7x4−5x3

2x3−15x2
2x3−15x2

28x2−15x2
28x2−15x2

28x3−15x2
28x3−15x2

Answer 1

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