Answer on Question #59990 – Math – Trigonometry
Question
1. Sketch 502∘502{}^{\circ}502∘ in standard position.
Solution
502∘=360∘+142∘502{}^{\circ} = 360{}^{\circ} + 142{}^{\circ}502∘=360∘+142∘, hence we obtain one full revolution and 142∘142{}^{\circ}142∘.
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