Question #59654

Solve triangle ABC which have angle A=25 25,angle B=60 51 and a=3.82 find c?

a)3-6

b)7.0

c)7.4

d)8.8

Expert's answer

Answer on Question #59654 – Math – Trigonometry

Question

Solve triangle ABC which have angle A=25 25, angle B=60 51 and a=3.82. Find c.

a) 3-6

b) 7.0

c) 7.4

d) 8.8

Solution

Angle


C=180(25.25+60.51)=94.24C = 180{}^\circ - (25.25{}^\circ + 60.51{}^\circ) = 94.24{}^\circ


Using the sine law


csinC=asinA,\frac{c}{\sin C} = \frac{a}{\sin A},


hence


c=asinCsinA=3.82sin94.24sin25.258.8c = a \frac{\sin C}{\sin A} = 3.82 \frac{\sin 94.24{}^\circ}{\sin 25.25{}^\circ} \approx 8.8


Answer: d) 8.8.

www.AssignmentExpert.com


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS