Question #58927

Just the answer please.
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Expert's answer

Answer on Question #58927 – Math – Trigonometry

Question

Solve on the interval [0,2π)[0, 2\pi):


4cscx+6=24cscx + 6 = -2π3,5π3\frac{\pi}{3}, \frac{5\pi}{3}2π3,4π3\frac{2\pi}{3}, \frac{4\pi}{3}π6,5π6\frac{\pi}{6}, \frac{5\pi}{6}7π6,11π6\frac{7\pi}{6}, \frac{11\pi}{6}

Solution

4cscx+6=2,0x<2π;4cscx + 6 = -2, 0 \leq x < 2\pi;4sinx=26;\frac{4}{\sin x} = -2 - 6;4sinx=8;\frac{4}{\sin x} = -8;sinx=12;\sin x = -\frac{1}{2};x=7π6 or x=11π6.x = \frac{7\pi}{6} \text{ or } x = \frac{11\pi}{6}.


Answer: 7π6,11π6\frac{7\pi}{6}, \frac{11\pi}{6}.

Question

Solve on the interval [0,2π)[0, 2\pi):


3secx2=13 \sec x - 2 = 1




π3,5π3\frac{\pi}{3}, \frac{5\pi}{3}π6,5π6\frac{\pi}{6}, \frac{5\pi}{6}2π3,4π3\frac{2\pi}{3}, \frac{4\pi}{3}

Solution

3secx2=1,0x<2π;3 \sec x - 2 = 1, \quad 0 \leq x < 2\pi;3cosx=1+2;\frac{3}{\cos x} = 1 + 2;3cosx=3;\frac{3}{\cos x} = 3;cos(x)=1;\cos(x) = 1;x=0.x = 0.


Answer: 0.

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Question

Which value is a solution for the equation tanx2=1\tan \frac{x}{2} = -1?


3π4\frac{3\pi}{4}7π4\frac{7\pi}{4}5π4\frac{5\pi}{4}3π2\frac{3\pi}{2}

Solution

tanx2=1;\tan \frac{x}{2} = -1;

x2=π4+nπ\frac{x}{2} = -\frac{\pi}{4} + n\pi, where nn is integer;


x=π2+2nπ.x = -\frac{\pi}{2} + 2n\pi.


If we take n=1n = 1, then


x=π2+2π=22ππ2=3π2.x = -\frac{\pi}{2} + 2\pi = \frac{2 \cdot 2\pi - \pi}{2} = \frac{3\pi}{2}.


Answer: 3π2\frac{3\pi}{2}.


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