Question

Just the answer please.
1: http://imgur.com/jqS3V1H
2: http://imgur.com/nKMR32j

Answer 1

Answer on Question #58899 – Math – Trigonometry

Question

$$\cos \left(\frac {19\pi}{6}\right) = \underline{\hspace{2cm}}$$ $$-\frac{1}{2}$$ $$\frac{1}{2}$$ $$-\frac{\sqrt{3}}{2}$$ $$\frac{\sqrt{3}}{2}$$

Solution

$$\cos \left(\frac {19\pi}{6}\right) = \cos \left(\frac {24\pi - 5\pi}{6}\right) = \cos \left(4\pi - \frac {5\pi}{6}\right) = \cos \left(-\frac {5\pi}{6}\right) = \cos \left(\frac {5\pi}{6}\right) = -\frac {\sqrt {3}}{2}.$$

Answer: $-\frac{\sqrt{3}}{2}$.

Question

$$\cot \left(\frac {25\pi}{2}\right) = \underline{\hspace{2cm}}$$

Undefined

- 1

1

Solution

$$\cot \left(\frac {25\pi}{2}\right) = \cot \left(\frac {24\pi + \pi}{2}\right) = \cot \left(12\pi + \frac {\pi}{2}\right) = \cot \left(\frac {\pi}{2}\right) = 0.$$

Answer: 0.

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