Question #58626

Just the answer please.
1: http://imgur.com/OV8dUWz

2: http://imgur.com/vnB3uVZ

Expert's answer

Answer on Question #58626 – Math – Trigonometry

Question

Which function’s graph has a period of 2?


y=2sinπxy=3cosxy=4sin2xy=cos(xπ2)\begin{array}{l} y = 2 \sin \pi x \\ y = 3 \cos x \\ y = -4 \sin 2x \\ y = \cos\left(x - \frac{\pi}{2}\right) \\ \end{array}

Solution

Let the unknown sine function be y=Asin(bx+c)+dy = A \sin(bx + c) + d

Then the period: T=tbT = \frac{t}{b}, where tt is a regular period of function (for example, regular period of sine and cosine t=2πt = 2\pi and for tangent and cotangent t=πt = \pi).

Our job is to find a function whose period is equal to 2. So in our formula, T=2T = 2. From the question it is clear that we need to look for these functions among the sine and cosine, then t=2πt = 2\pi.

Substitute the values into the formula:


2=2πb,2 = \frac{2\pi}{b},


hence


b=2π2=π.b = \frac{2\pi}{2} = \pi.


We also know that bb is the coefficient of xx, so we now find the function whose coefficient near xx is π\pi. That’s only one function:


y=2sinπxy = 2 \sin \pi x


**Answer:**


y=2sinπxy = 2 \sin \pi x

Question

Which description matches the transformation y=cosxy = \cos x undergoes to produce y=3cos(2x)y = 3\cos (-2x) ?

Reflection through the y-axis, vertical shift of 2 units, horizontal shift right by 3 units.

Horizontal shift left 2 units, then vertical shift up by 3 units.

Horizontal compression by factor 12\frac{1}{2} , vertical stretch by factor 3, then a reflection through the y-axis.

Horizontal stretch by factor 2, reflection through the x-axis, then vertical stretch by factor 3.

Solution

Transformations "after" the original function.



Transformations "before" the original function.



Suppose that we have a function y=cosxy = \cos x . To transform it, we do the following steps:

1. y=cos(2x)y = \cos (2x) : we have to shrink the function y=cosxy = \cos x horizontally by 12\frac{1}{2} .

2. y=3cos(2x)y = 3\cos (2x) : the function y=cos(2x)y = \cos (2x) is stretched vertically by 3.

3. y=3cos(2x)y = 3\cos (-2x) : the final step is to flip the function y=3cos(2x)y = 3\cos (2x) over the y-axis.

Answer:

Horizontal compression by factor 12\frac{1}{2} , vertical stretch by factor 3, then a reflection through the y-axis.

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