Answer on Question #58626 – Math – Trigonometry
Question
Which function’s graph has a period of 2?
Solution
Let the unknown sine function be
Then the period: , where is a regular period of function (for example, regular period of sine and cosine and for tangent and cotangent ).
Our job is to find a function whose period is equal to 2. So in our formula, . From the question it is clear that we need to look for these functions among the sine and cosine, then .
Substitute the values into the formula:
hence
We also know that is the coefficient of , so we now find the function whose coefficient near is . That’s only one function:
**Answer:**
Question
Which description matches the transformation undergoes to produce ?
Reflection through the y-axis, vertical shift of 2 units, horizontal shift right by 3 units.
Horizontal shift left 2 units, then vertical shift up by 3 units.
Horizontal compression by factor , vertical stretch by factor 3, then a reflection through the y-axis.
Horizontal stretch by factor 2, reflection through the x-axis, then vertical stretch by factor 3.
Solution
Transformations "after" the original function.
Transformations "before" the original function.
Suppose that we have a function . To transform it, we do the following steps:
1. : we have to shrink the function horizontally by .
2. : the function is stretched vertically by 3.
3. : the final step is to flip the function over the y-axis.
Answer:
Horizontal compression by factor , vertical stretch by factor 3, then a reflection through the y-axis.
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