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Answer to Question #56476 in Trigonometry for jonah
Question #56476
Solve the following for 0 ≤ θ ≤ 720°
a) 3cosθ – 2 = 0
b) 2sin2θ – sinθ – 1 = 0
Solve the following for -2π ≤ θ ≤ 2π
a) 3tan2θ – 1 = 0
b) 12cos2θ – 6 = sinθ
a) 3cosθ – 2 = 0
b) 2sin2θ – sinθ – 1 = 0
Solve the following for -2π ≤ θ ≤ 2π
a) 3tan2θ – 1 = 0
b) 12cos2θ – 6 = sinθ
Expert's answer
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#339914 on Dec 2023
#339914 on Dec 2023
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