Answer on Question #51810 – Math – Trigonometry
Question
Without using tables, find the value of tan 450
A 3
B 5
C 2
D 1
Solution
Take the unit circle, the triangle is right-angled, therefore x = cos ( α ) x = \cos(\alpha) x = cos ( α ) ,
y = sin ( α ) y = \sin(\alpha) y = sin ( α ) and x 2 + y 2 = 1 x^2 + y^2 = 1 x 2 + y 2 = 1 . Besides, the triangle is isosceles, therefore
x = y x = y x = y .
If the triangle is right-angled and isosceles, then its interior angles are 45 ∘ 45{}^\circ 45 ∘ , 45 ∘ 45{}^\circ 45 ∘ , 90 ∘ 90{}^\circ 90 ∘ .
Solving the system of equations
{ x 2 + y 2 = 1 , x = y , \left\{ \begin{array}{c} x^2 + y^2 = 1, \\ x = y, \end{array} \right. { x 2 + y 2 = 1 , x = y ,
substitute y = x y = x y = x and the first equation gives
x 2 + x 2 = 1 x^2 + x^2 = 1 x 2 + x 2 = 1 2 x 2 = 1 2x^2 = 1 2 x 2 = 1 x = 1 / 2 x = \sqrt{1/2} x = 1/2 x = 2 2 . x = \frac{\sqrt{2}}{2}. x = 2 2 .
Thus, x = y = 2 2 x = y = \frac{\sqrt{2}}{2} x = y = 2 2 . In other words, cos ( 45 ∘ ) = sin ( 45 ∘ ) = 2 2 \cos(45{}^\circ) = \sin(45{}^\circ) = \frac{\sqrt{2}}{2} cos ( 45 ∘ ) = sin ( 45 ∘ ) = 2 2 .
tan 45 ∘ = sin 45 ∘ cos 45 ∘ = 2 2 = 1 ; \tan 45{}^{\circ} = \frac{\sin 45{}^{\circ}}{\cos 45{}^{\circ}} = \frac{\sqrt{2}}{\sqrt{2}} = 1; tan 45 ∘ = cos 45 ∘ sin 45 ∘ = 2 2 = 1 ;
Answer: D 1.
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