Answer for Question 50664, Math, Trigonometry:
cos−1(−x)=arccos(−x)=π−arccos(x)=π−cos−1(x).sec−1(−x)=\arcsec(−x)=arccos(−x1)=cos−1(−x1).\arcsec(−x)=A;−x=secA;x=−secA;x=−cosA1;cosA=−x1;A=arccos(−x1);\arcsec(−x)=arccos(−x1).
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