Question #50664

cos^(-1)⁡(-x)= - cos^(-1)⁡(x)or cos^(-1)⁡(x) ?? which one is correct?

sec^(-1)⁡(-x)= - sec^(-1)⁡(x)or sec^(-1)⁡(x) ?? which one is correct?
1

Expert's answer

2015-02-19T12:03:46-0500

Answer for Question 50664, Math, Trigonometry:


cos1(x)=arccos(x)=πarccos(x)=πcos1(x).\cos^{-1}(-x) = \arccos(-x) = \pi - \arccos(x) = \pi - \cos^{-1}(x).sec1(x)=\arcsec(x)=arccos(1x)=cos1(1x).\sec^{-1}(-x) = \arcsec(-x) = \arccos\left(-\frac{1}{x}\right) = \cos^{-1}\left(-\frac{1}{x}\right).\arcsec(x)=A;\arcsec(-x) = A;x=secA;- x = \sec A;x=secA;x = -\sec A;x=1cosA;x = -\frac{1}{\cos A};cosA=1x;\cos A = -\frac{1}{x};A=arccos(1x);A = \arccos\left(-\frac{1}{x}\right);\arcsec(x)=arccos(1x).\arcsec(-x) = \arccos\left(-\frac{1}{x}\right).


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