Answer to Question #4684 in Trigonometry for Deepu K Sam

Question

Elevation of a tower at a Station A due north of it is x and at a Station B due wist of A is y. Prove that height or the tower is AB*(sin(x)*sin(y))/sqrt(sin^2(x)-sin^2(y))

Answer 1

Unfortunately it's not clear from the question what are x and y.