Question #46597

Prove-

sin^3A * sin^3(120+A) * sin^3(sin240+A) = 3/4 cos3A

Expert's answer

Answer on Question #46597 – Math – Trigonometry

Prove-


sin23Asin23(120+A)sin23(sin240+A)=3/4cos3A\sin^2 3 A ^ {*} \sin^2 3 (1 2 0 + A) ^ {*} \sin^2 3 (\sin 2 4 0 + A) = 3 / 4 \cos 3 A


Solution.

This equality is not true, because

for A=0A = 0 , sinA=0\sin A = 0 , cosA=1\cos A = 1 , and we have 0=340 = \frac{3}{4}

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