Question

The value of three angles at a piont are
3y−45^0,y+25^0andy^0
. Find the value of y.
56^0
86^0
78^0
76^0

Answer 1

Answer on Question #46306 - Math - Trigonometry

The value of three angles at a point are $3y - 45{}^{\circ}0, y + 25{}^{\circ}0$ and $y{}^{\circ}0$. Find the value of y.

56°0

86°0

78°0

76°0

Solution:

We have three angles at point A (see picture). Sum all this angles is equal $360{}^{\circ}$ (degrees). (Sum all angles at a point is equal $360{}^{\circ}$).

Therefore obtain the equation

$$(3y - 45{}^{\circ}) + (y + 25{}^{\circ}) + y = 360{}^{\circ}$$

Solve it

$$\begin{array}{l} 5y - 20{}^{\circ} = 360{}^{\circ} \\ 5y = 380{}^{\circ} \\ y = \frac{380{}^{\circ}}{5} = 76{}^{\circ} \\ \end{array}$$

Answer: $y = 76{}^{\circ}$

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