Question

Y=25cos (3.14t/3)+27

What is the frequency of motion in hertz?

Answer 1

Answer on Question 43300 – Math – Trigonometry

Y=25cos(3.14t/3)+27

What is the frequency of motion in hertz?

Solution.

General form of harmonic law of motion is $y = A\cos (\omega t + \delta) + B$

We are given $y = 25\cos (3.14\frac{t}{3}) + 27 = 25\cos (\frac{\pi}{3} t) + 27$ $\omega = \frac{\pi}{3}$ - this is the angular frequency.

The relation between angular frequency and frequency is $\omega = 2\pi \nu$

Thus, frequency (in hertz) is $\nu = \frac{\omega}{2\pi} = \frac{\pi}{3}\frac{1}{2\pi} = \frac{1}{6} Hz \approx 0.167 Hz$

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