Question

How do you find

cotx=√3

1/cosx=-1/4

Answer in radians

Answer 1

Answer on Question #41691, Math, Statistics and Probability

How do you find

a. $\cot x = \sqrt{3}$

b. $1 / \cos x = -1 / 4$

Answer in radians.

Solution

a. If $\cot x = \sqrt{3}$ then

$$x = \cot^ {- 1} \sqrt {3} + \pi n = \frac {\pi}{6} + \pi n, \text { where } n \text { is integer}.$$

b. If $\frac{1}{\cos x} = -\frac{1}{4}$ then $\cos x = -4$ . This equation has no solution because range of cosine is [-1;1].

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