Question #39428

Find theta for 0 degrees equal or less then theta less then 360 degrees that satisfies the stated condition.

tan theta = -0.6 and sin theta is less then zero
1

Expert's answer

2014-02-25T03:13:36-0500

Answer on Question#39428, Math, Trigonometry

We are given 0<θ<2π0 < \theta < 2\pi , tgθ=0.6tg\theta = -0.6 , sinθ<0\sin \theta < 0

Since tgθ=sinθcosθ=0.6<0tg\theta = \frac{\sin\theta}{\cos\theta} = -0.6 < 0 and sinθ<0\sin \theta < 0 , thus cosθ>0\cos \theta > 0 , so π2<θ<π2\frac{-\pi}{2} < \theta < \frac{\pi}{2} . Solution θ=arctan(0.6)30.96\theta = \arctan(-0.6) \approx -30.96 degrees satisfies given conditions.


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