Question #38772

length of ramp is 20 ft. find height and base

Expert's answer

Answer on Question#38772 - Math - Trigonometry

Question.

Length of ramp is 20 ft. find height and base.

Solution

A ramp is a flat supporting surface tilted at an angle, with one end higher than the other. The inclined plane's geometry is based on a right triangle. The horizontal leg length is called base, the vertical leg length is called height. (See the figure below.)



The length of ramp is given, i. e. l=20l = 20 . Let bb and hh denote the base and the height, respectively. To determine the length bb of the base, we can use the cosine function.


cosα=bl\cos \alpha = \frac {b}{l}


Multiplying by ll and substituting 20 for ll we obtain


b=lcosα=20cosα.b = l \cos \alpha = 2 0 \cos \alpha .


We use the sine function to find the height


sinα=hl\sin \alpha = \frac {h}{l}


In a similar manner as above we obtain


h=lsinα=20sinα.h = l \sin \alpha = 2 0 \sin \alpha .


Because the angle α\alpha is not given, one can see that the solution of the problem is not unique. If we take α=30\alpha = 30{}^{\circ} , then we get


b=lcos30=20cos30=200,8660=17,32ft,b = l \cos 3 0 {}^ {\circ} = 2 0 \cos 3 0 {}^ {\circ} = 2 0 \cdot 0, 8 6 6 0 = 1 7, 3 2 \mathrm {f t},h=lsin30=20sin30=200,5=10ft.h = l \sin 3 0 {}^ {\circ} = 2 0 \sin 3 0 {}^ {\circ} = 2 0 \cdot 0, 5 = 1 0 \mathrm {f t}.


But if we take α=45\alpha = 45{}^{\circ} , then we obtain


b=lcos45=20cos45=200,7071=14,142ft,b = l \cos 4 5 {}^ {\circ} = 2 0 \cos 4 5 {}^ {\circ} = 2 0 \cdot 0, 7 0 7 1 = 1 4, 1 4 2 \mathrm {f t},h=lsin45=20sin45=200,7071=14,142ft.h = l \sin 4 5 {}^ {\circ} = 2 0 \sin 4 5 {}^ {\circ} = 2 0 \cdot 0, 7 0 7 1 = 1 4, 1 4 2 \mathrm {f t}.


That is in the last case the height and base are equal.

Answers:

b=lcosα,h=lsinαb = l \cos \alpha , h = l \sin \alpha

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