Answer to Question #348517 in Trigonometry for goody hoody

Question

a balloon is 50m high its angle of elevation from observer A is 45 and from observer B it is 30 what is the distance between observer b and observer a from the baloon

Answer 1

$x=\dfrac{h}{\tan\theta}$

$x_A=\dfrac{50}{\tan45\degree}=50(m)$

$x_B=\dfrac{50}{\tan30\degree}=50\sqrt{3}(m)$

Maximum distance

$d_{max}=x_A+x_B=50+50\sqrt{3}=50(1+\sqrt{3})(m)$

$\approx136.6(m)$

Minimum distance

$d_{max}=-x_A+x_B=-50+50\sqrt{3}=50(\sqrt{3}-1)(m)$

$\approx36.6(m)$