Answer for Question 34604, Math, Trigonometry:
In this right triangle ABC hypotenuse ABABAB is equal 65 and ∠A=60∘\angle A = 60{}^{\circ}∠A=60∘.
The opposite leg BC=AB∗sin∠A=65∗sin60∘≈56.29BC = AB * \sin \angle A = 65 * \sin 60{}^{\circ} \approx 56.29BC=AB∗sin∠A=65∗sin60∘≈56.29
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