Question #341801
Solve the triangle.
A = 21°, C = 105 °, c = 5
Expert's answer
B=1800-1050-210=540
a/sinA=b/sinB=c/sinC
a/sin210=b/sin540=5/sin1050
a=5sin210/sin1050=5*0.3589/0.9659=1.85
b=5sin540/sin1050=5*0.809/0.9659=4.18
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