Question #33819

Let tan tanx=2 . Which is cot x?

Expert's answer

1. Let tantanx=2tantanx = 2. Which is cotxcotx?

Solution.

Firstly, let solve the equation


tantanx=2tantanx = 2


for tanxtanx.

As 2>02 > 0, then we ought to use the following roots of the equation tany=atany = a:


y=arctana+πn,nZ.y = arctana + \pi n, \quad n \in \mathbb{Z}.


So, one can receive:


tanx=arctan2+πn,nZ.tanx = arctan2 + \pi n, \quad n \in \mathbb{Z}.


Now, we shall use the trigonometric identity


tanycoty=1,tany \cdot coty = 1,


which observes for all yπk2y \neq \frac{\pi k}{2}, kZk \in \mathbb{Z}.

As arctan2+πnarctan2 + \pi n does not equal to πk2\frac{\pi k}{2} for any integer nn and kk, then


cotx=1tanx=1arctan2+πn,nZ.cotx = \frac{1}{tanx} = \frac{1}{arctan2 + \pi n}, \quad n \in \mathbb{Z}.


Answer: cotx=1arctan2+πncotx = \frac{1}{arctan2 + \pi n}, nZn \in \mathbb{Z}.

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