Question #337593

Evaluate



a) sin (alpha), given that sec (alpha)= -3, and that alpha is an obtuse angle.


b) cot(beta), given that tan(beta)=1/(√2) and that beta is an acute angle.

1
Expert's answer
2022-05-06T11:15:41-0400

a) 90°<α<180°90\degree<\alpha<180\degree


cosα=1secα=13\cos \alpha=\dfrac{1}{\sec \alpha}=-\dfrac{1}{3}

sinα=1cos2α=1(13)2=223\sin \alpha=\sqrt{1-\cos^2 \alpha}=\sqrt{1-(-\dfrac{1}{3})^2}=\dfrac{2\sqrt{2}}{3}

b) 0°<α<90°0\degree<\alpha<90\degree


cotβ=1tanβ=2\cot \beta=\dfrac{1}{\tan \beta}=\sqrt{2}


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