Question #33564

Let cos x = .28 and cos y = .74. Which is x – y?

A. cos^(–1).28 + cos^(–1).74
B. –cos^(–1).28 – cos^(–1).74
C. cos^(–1).28 – cos^(–1).74
D. –cos^(–1).28 + cos&(–1).74

Expert's answer

Let cosx=.28\cos x = .28 and cosy=.74\cos y = .74. Which is xyx - y?

A. cos10.28+cos10.74\cos^{-1}0.28 + \cos^{-1}0.74

B. cos10.28cos10.74-\cos^{-1}0.28 - \cos^{-1}0.74

C. cos10.28cos10.74\cos^{-1}0.28 - \cos^{-1}0.74

D. cos10.28+cosamp;(1).74-\cos^{-1}0.28 + \cos \text{amp}; (-1).74

**Solution:**

Let us solve each equation:


cosx=0.28\cos x = 0.28x=±cos10.28+2πk,kinteger constantx = \pm \cos^{-1} 0.28 + 2\pi k, \quad k - \text{integer constant}cosy=0.74\cos y = 0.74y=±cos10.74+2πn,ninteger constanty = \pm \cos^{-1} 0.74 + 2\pi n, \quad n - \text{integer constant}


Now we can simply find the difference between xx and yy:

1. Angles in the range 0<x<π,0<y<π0 < x < \pi, 0 < y < \pi:


xy=cos10.28cos10.74x - y = \cos^{-1} 0.28 - \cos^{-1} 0.74


Correct answer in this case is C

2. For all angles:

Since trigonometric equation has not one solution, all responses are correct because of the ambiguity of the angle (it may be x=cos10.28,cos10.28,cos10.28+2πk,x = \cos^{-1} 0.28, -\cos^{-1} 0.28, \cos^{-1} 0.28 + 2\pi k, \ldots,


y=cos10.74,cos10.74,cos10.28+2πk,)y = \cos^{-1} 0.74, -\cos^{-1} 0.74, \cos^{-1} 0.28 + 2\pi k, \ldots)xy=cos10.28(cos10.74)=cos10.28+cos10.74 (answer A)x - y = \cos^{-1} 0.28 - (-\cos^{-1} 0.74) = \cos^{-1} 0.28 + \cos^{-1} 0.74 \text{ (answer A)}xy=cos10.28(cos10.74)=cos10.28cos10.74 (answer B)x - y = -\cos^{-1} 0.28 - (\cos^{-1} 0.74) = -\cos^{-1} 0.28 - \cos^{-1} 0.74 \text{ (answer B)}xy=cos10.28(cos10.74)=cos10.28cos10.74 (answer C)x - y = \cos^{-1} 0.28 - (\cos^{-1} 0.74) = \cos^{-1} 0.28 - \cos^{-1} 0.74 \text{ (answer C)}xy=cos10.28(cos10.74)=cos10.28+cos10.74 (answer D)x - y = -\cos^{-1} 0.28 - (-\cos^{-1} 0.74) = -\cos^{-1} 0.28 + \cos^{-1} 0.74 \text{ (answer D)}


**Answer:** Angles in the range 0<x<π,0<y<π0 < x < \pi, 0 < y < \pi: correct answer: C

For all angles: all answers are correct: A, B, C, D,

For the correct solution of the problem we need to know possible values of the angles xx and yy.

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