Question #32197

If sin a = .25 and cos b = .25, which of the following is sin b/2 + cos a/2 ?

A. 1.60
B. 1.32
C. .26
D. 1.06

Expert's answer

If sina=0.25\sin a = 0.25 and cosb=0.25\cos b = 0.25, which of the following is sinb/2+cosa/2\sin^b /_2 + \cos^a /_2?

A. 1.60

B. 1.32

C. 0.26

D. 1.06

**Solution.**

Since sina=0.25>0\sin a = 0.25 > 0 then a(0,π)a \in (0, \pi) where sine is a positive value.

Since cosb=0.25>0\cos b = 0.25 > 0 then b(0,π)b \in (0, \pi) where cosine is a positive value.

So sinb2>0\sin \frac{b}{2} > 0 and cosa2>0\cos \frac{a}{2} > 0.

Express sinb/2=f(cosb)\sin^b /_2 = f(\cos b):

We have the formula:


sin2α=1cos2α2\sin^2 \alpha = \frac{1 - \cos 2\alpha}{2}


Use it:


sin2b2=1cosb2\sin^2 \frac{b}{2} = \frac{1 - \cos b}{2}


Then


sinb2=1cosb2=10.252=0.3750.61\sin \frac{b}{2} = \sqrt{\frac{1 - \cos b}{2}} = \sqrt{\frac{1 - 0.25}{2}} = \sqrt{0.375} \approx 0.61


Similarly, express cosa/2=f(sina)\cos^a /_2 = f(\sin a):

Use this formula cos2α=1+cos2α2\cos^2 \alpha = \frac{1 + \cos 2\alpha}{2}:


cos2a2=1+cosa2=1+1sin2a2=1+10.062520.99\cos^2 \frac{a}{2} = \frac{1 + \cos a}{2} = \frac{1 + \sqrt{1 - \sin^2 a}}{2} = \frac{1 + \sqrt{1 - 0.0625}}{2} \approx 0.99


So calculate sinb/2+cosa/2\sin^b /_2 + \cos^a /_2:


sinb/2+cosa/2=0.61+0.99=1.6\sin^b /_2 + \cos^a /_2 = 0.61 + 0.99 = 1.6


**Answer:** A. 1.60

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