Question #32195

Let sin m = .11. Which of the following is sin m/2?

A. .79
B. .78
C. .77
D. .05

Expert's answer

Task. Let sinm=0.11\sin m=0.11. Which of the following is sin(m/2)\sin(m/2)?

A. 0.790.79

B. 0.780.78

C. 0.770.77

D. 0.050.05

Solution. Notice that

cosm=1sin2m=10.112=0.98790.99393\cos m=\sqrt{1-\sin^{2}m}=\sqrt{1-0.11^{2}}=\sqrt{0.9879}\approx 0.99393

and

cos2(m/2)=1+cosm2=1+0.993932=0.996965.\cos^{2}(m/2)=\frac{1+\cos m}{2}=\frac{1+0.99393}{2}=0.996965.

Therefore

sin(m/2)=1cos2(m/2)=10.996965=0.0030350.05.\sin(m/2)=\sqrt{1-\cos^{2}(m/2)}=\sqrt{1-0.996965}=\sqrt{0.003035}\approx 0.05.

Thus the answer is D. 0.050.05

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