Task. Let sinm=0.11. Which of the following is sin(m/2)?
A. 0.79
B. 0.78
C. 0.77
D. 0.05
Solution. Notice that
cosm=1−sin2m=1−0.112=0.9879≈0.99393
and
cos2(m/2)=21+cosm=21+0.99393=0.996965.
Therefore
sin(m/2)=1−cos2(m/2)=1−0.996965=0.003035≈0.05.
Thus the answer is D. 0.05