If tan A + sec A =L , then prove that (L2+L)/2L = sec A
(* note L2 is L square)
1
Expert's answer
2014-03-07T05:39:44-0500
This equality (L2+L)/2L=sec(A) is incorrect. Prove: (L2+L)/2L=L/2+1/2=sec (A). So, we obtain that L+1=2sec(A) or tan(A)+sec(A)+1=2sec(A). From this tan(A)+1=sec(A) - but it's wrong equality, because tan^2(A)+1=sec^2(A).
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