Task. If sinx=0.20, cosx=0.98, siny=0.12, and cosy=0.99, which of the following is sin(x+y)?
A) 0.32
B) 0.33
C) 0.29
D) 0.28
Solution. Recall that
sin(x+y)=sinxcosy+cosxsiny.
Substituting values we get
sin(x+y)=sinxcosy+cosxsiny=0.20∗0.99+0.98∗0.12=0.3156≈0.32.
Answer. A) sin(x+y)≈0.32.