Question #31677

If sin x = 0.20, cos x = .98, sin y = .12, and cos y = .99, which of the following is sin (x + y)?

A. .32
B. .33
C. .29
D. .28

Expert's answer

Task. If sinx=0.20\sin x = 0.20, cosx=0.98\cos x = 0.98, siny=0.12\sin y = 0.12, and cosy=0.99\cos y = 0.99, which of the following is sin(x+y)\sin(x + y)?

A) 0.32

B) 0.33

C) 0.29

D) 0.28

Solution. Recall that


sin(x+y)=sinxcosy+cosxsiny.\sin(x + y) = \sin x \cos y + \cos x \sin y.


Substituting values we get


sin(x+y)=sinxcosy+cosxsiny=0.200.99+0.980.12=0.31560.32.\sin(x + y) = \sin x \cos y + \cos x \sin y = 0.20 * 0.99 + 0.98 * 0.12 = 0.3156 \approx 0.32.


Answer. A) sin(x+y)0.32\sin(x + y) \approx 0.32.


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