Conditions
Write in Logarithmic Form:
A. Log (base 125) 5=35 = 35=3
B. Log (base 3) 125=5125 = 5125=5
C. Log (base 5) 125=3125 = 3125=3
Solution
The correct Logarithmic Form is C. Log (base 5) 125=3125 = 3125=3
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