Question 31430
One needs to solve equation log3x=2\log_3 x = 2log3x=2 .
According to the definition of logarithm, ab=c⇔logac=ba^b = c \Leftrightarrow \log_a c = bab=c⇔logac=b . Hence, x=32=9x = 3^2 = 9x=32=9 . The answer is B).
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