Question #311453

Solve the equation √3sin𝜃−cos𝜃=0 for −180°≤𝑥≤180°


1
Expert's answer
2022-03-15T09:27:45-0400

3sinθ=cosθ;sinθcosθ=13;tanθ=13;θ=arctan13+180°n=30°+180°n,  nZ;\sqrt{3} \sin\theta=\cos \theta;\\ \cfrac{\sin\theta}{\cos\theta}=\cfrac{1}{\sqrt3};\\ \tan\theta=\cfrac{1}{\sqrt3};\\ \theta=\arctan\cfrac{1}{\sqrt3}+180\degree\cdot n=30\degree+180\degree\cdot n, \ \ n\in Z;\\

for 180°θ180°  n=0-180\degree\leq\theta\leq180\degree\ \ n=0 or n=1;n=-1;

θ1=150°,  θ2=30°.\theta_1=-150\degree,\ \ \theta_2=30\degree.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS