If there is a square of side 'a'. At the centre of the square there is situated a tower of height 'h', from the top of the tower the angle at the top and the line joining the vertex is 60 degrees. Find the height of the tower?
AC = √(AD2 + DC2) = √(AD2) = a√2
OC = 1/2 AC = a/√2
OH = OC/tan(60) = a/√(2*3) = a/√6
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